Liquids A and B are at `30^(@)` C and `20^(@)` C, respectively. When mixed in equal masses,the temperature of the mixture is found to be `26^(@)` C, The specific heats of A and B are in the ratio of `m:n`, where m and n are integers, then find minimum value of `m+n`.

Answer

5

Explanation

At thermal equilibrium heat rejected by one liquid = heat accepted by another liquid
`mS_(A)(30 -26) = mS_(B) (26-20)`
`rArr 4S_(A) = 6S_(B)`
`therefore S_(A)/S_(B) = 6/4 = 3/2 = m/n rArr m + n = 3 + 2 = 5`