Home
Class 12
PHYSICS
If the density of a planet is constant, ...

If the density of a planet is constant, then the curve between value of g on its surface and its radius r will be-

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A

Here r is the radius of the planet. Then, the acceleration due to gravity at the surface of the planet,
`g=(GM)/(r^(2))=(G_(rho)(4)/(3)pir^(3))/(r^(2))=(4)/(3)piGrhor`
This meang increases linearly with increase in r, keeping density constant. Hence, the graph is straight line.
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 108

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos
  • NTA TPC JEE MAIN TEST 107

    NTA MOCK TESTS|Exercise PHYSICS|30 Videos
  • NTA TPC JEE MAIN TEST 109

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos

Similar Questions

Explore conceptually related problems

If the radius of a planet is R and its density is rho , the escape velocity from its surface will be

If different planets have the same density but diferent radii then the acceleration due to gravity (g) on the surface of the planet will depend on its radius (R) as

A planet has twice the density of earth but the acceleration due to gravity on its surface is exactly the same as that on the surface of earth. Its radius in terms of earth's radius R will be

If the density of the earth is doubled keeping its radius constant then acceleration due to gravity will be (g=9.8 m//s^(2))

The density of a planet PL1 is thrice that of planet PL2. The acceleration due to gravity at the surface of PL1 is (1^(th))/(9) of that at the surface of planet PL2. If the radius of planet PL2 is R, then the radius of planet PL1 will be

The acceleration due to gravity at the surface of earth (g_(e)) and acceleration due to gravity at the surface of a planet (g_(p)) are equal. The density of the planet is three times than that of earth. The ratio of radius of earth to the radius of planet will be.

If the density of a small planet is the same as that of earth while the radius of the planet is 0.2 times that of the earth the gravitational on the surface of that planet is :