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The point(s), at which the function f gi...

The point(s), at which the function f given by `f(x) = {{:((x),xlt0),(-1,xge0):}` is continuous, is/are:

A

`x in R`

B

`x =0`

C

`x in R-{0}`

D

`x = -1 and 1`

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The correct Answer is:
To determine the points at which the function \( f(x) \) is continuous, we need to analyze the function defined as: \[ f(x) = \begin{cases} x & \text{if } x < 0 \\ -1 & \text{if } x \geq 0 \end{cases} \] ### Step 1: Understand Continuity A function is continuous at a point \( a \) if: \[ \lim_{x \to a} f(x) = f(a) \] This means that the left-hand limit and the right-hand limit at that point must equal the function's value at that point. ### Step 2: Check Continuity at \( x = 0 \) We need to check the continuity at the point \( x = 0 \) since the function has different definitions for \( x < 0 \) and \( x \geq 0 \). #### Step 2.1: Calculate \( f(0) \) From the definition of the function: \[ f(0) = -1 \quad \text{(since \( 0 \geq 0 \))} \] #### Step 2.2: Calculate the Right-Hand Limit We calculate the limit as \( x \) approaches \( 0 \) from the right: \[ \lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} (-1) = -1 \] #### Step 2.3: Calculate the Left-Hand Limit Now we calculate the limit as \( x \) approaches \( 0 \) from the left: \[ \lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} x = 0 \] ### Step 3: Compare Limits and Function Value Now we compare the limits and the function value: - \( \lim_{x \to 0^+} f(x) = -1 \) - \( \lim_{x \to 0^-} f(x) = 0 \) - \( f(0) = -1 \) Since the left-hand limit \( (0) \) does not equal the right-hand limit \( (-1) \), and the function value \( f(0) \) does not equal the left-hand limit, we conclude that: \[ \text{The function is not continuous at } x = 0. \] ### Step 4: Determine Continuity Elsewhere Since the function is defined as \( f(x) = x \) for \( x < 0 \) and \( f(x) = -1 \) for \( x \geq 0 \), we can see that: - For \( x < 0 \), \( f(x) = x \) is a linear function and is continuous everywhere in that interval. - For \( x > 0 \), \( f(x) = -1 \) is a constant function and is also continuous everywhere in that interval. ### Conclusion Thus, the function \( f(x) \) is continuous for all \( x \) except at \( x = 0 \). Therefore, the points at which the function is continuous are: \[ \text{The function is continuous for } x \in \mathbb{R} \setminus \{0\}. \] ### Final Answer The correct option is: \( x \in \mathbb{R} - \{0\} \). ---
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