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The point on the curve x^2=2ywhich is ne...

The point on the curve `x^2=2y`which is nearest to the point (0, 5) is(A) `(2sqrt(2),4)` (B) `(2sqrt(2),0)` (C) (0, 0) (D) (2, 2)

A

(0, 0)

B

(2, 2)

C

(5, 9)

D

`(2sqrt(2), 4)`

Text Solution

Verified by Experts

The correct Answer is:
D
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