Force of 12 N is experienced by two charges of +8 `mu `C and - 6 `mu` C. A charge of + 4 `mu` C is added. The new force between the charges will be:

Options

A. 2 N
B. 24 N
C. 6 N
D. 12 N

Answer

C

Explanation

As `F prop q_(1) q_(2)`
`(F)/(F) = (q_(1)q_(2))/(q_(1)q_(2))`
`= ((+8 +4)(-6 +4))/((+8)(-6))`
=`(1)/(2)`
Now `F = 12N `
`:. (F)/(12) = (1)/(2)`
`implies F= 6 N`