Home
Class 12
PHYSICS
Magnetic field of a straight solenoid ca...

Magnetic field of a straight solenoid carrying carried 1 and having a n turns per unit length given by:

A

`B = (mu_(0)n I)/(2)`

B

`B = mu_(0) n I`

C

`B = mu_(0)n^(2)I`

D

`(mu_(0) n^(2)I)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B

`mu_(0)N = B(L)`
`B = (mu_(0)N I)/(L)`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER - 8

    EDUCART PUBLICATION|Exercise Section B|24 Videos
  • SAMPLE PAPER - 8

    EDUCART PUBLICATION|Exercise Section C|6 Videos
  • CBSE TERM-1 SAMPLE PAPER 1

    EDUCART PUBLICATION|Exercise SECTION-C|6 Videos
  • SAMPLE PAPER 04 (SOLVED)

    EDUCART PUBLICATION|Exercise SECTION-C|6 Videos

Similar Questions

Explore conceptually related problems

Derive an expression for the magnetic field due to a solenoid of length 2l , radius a, having n number of turns per unit length and carrying a steady current I, at a point on the axial line, distant r from the centre of the solenoid. How does this expression compare with the axial magnetic field due to a bar magnet of magnetic moment M?

State Ampere's circuital law. Use this law to obtain the expression for the magnetic field inside an air cored toroid of average radius r having n-turns per unit length and carrying a steady current I.

The magnetic field in a straight current carrying conductor wire is: