The relation of conducting of solid conductor is given by:

Options

A. `sigma = (n e^(2))/(m) Z`
B. `sigma = (2n e^(2))/(m) Z`
C. `sigma = (n e^(2))/(4m) Z`
D. `sigma = (n e^(2))/(2m) Z`

Explanation

To solve the question regarding the relation of conductivity in a solid conductor, we can break it down into steps:

### Step 1: Understanding Conductivity
Conductivity (σ) is a measure of a material's ability to conduct electric current. It is defined as the ratio of the current density (J) to the electric field (E) applied to the conductor.

### Step 2: Write the Formula
The relationship can be expressed mathematically as:
\[ J = \sigma E \]
Where:
- \( J \) is the current density (current per unit area, measured in A/m²),
- \( \sigma \) is the conductivity of the material (measured in S/m),
- \( E \) is the electric field (measured in V/m).

### Step 3: Rearranging the Formula
From the equation \( J = \sigma E \), we can rearrange it to express conductivity:
\[ \sigma = \frac{J}{E} \]

### Step 4: Interpretation
This equation indicates that the conductivity of a solid conductor is directly proportional to the current density and inversely proportional to the electric field applied. A higher conductivity means that the material can carry more current for a given electric field.

### Step 5: Conclusion
Thus, the relation of conductivity in a solid conductor can be summarized as:
\[ \sigma = \frac{J}{E} \]