Assertion (A): Resistances connected in parallel has higher equivalent resistance.
Reason (R): `R_(P) = R_(1) + R_(2) + …. + R_(n)`

Options

A. Both (A) and (R) are true and (R) is the correct explanation of (A).
B. Both (A) and (R) are true but (R) is not the correct explanation of (A).
C. (A) is true but (R) is false.
D. (A) is false and (R) is also false.

Explanation

To solve the assertion and reason question, let's analyze both the assertion (A) and the reason (R) step by step.

### Step 1: Understand the Assertion (A)
The assertion states that "Resistances connected in parallel have higher equivalent resistance."

**Analysis**:
- When resistors are connected in parallel, the total or equivalent resistance (R_P) is always less than the smallest individual resistance in the group. This is because the current can take multiple paths, effectively reducing the overall resistance.

### Step 2: Understand the Reason (R)
The reason states that "R_P = R_1 + R_2 + ... + R_n."

**Analysis**:
- This equation actually describes the total resistance for resistors connected in series, not in parallel. For resistors in parallel, the correct formula is:
\[ \frac{1}{R_P} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n} \]
This means that the equivalent resistance decreases as more resistors are added in parallel.

### Step 3: Conclusion
Since the assertion is incorrect (parallel resistances do not have higher equivalent resistance) and the reason is also incorrect (the formula given is for series resistances), both the assertion (A) and the reason (R) are false.

### Final Answer
Both the assertion (A) and the reason (R) are false.