To solve the question "If there is no charge enclosed then:", we can use Gauss's Law, which relates the electric flux through a closed surface to the charge enclosed by that surface.
### Step-by-Step Solution:
1. **Understanding Gauss's Law**:
Gauss's Law states that the electric flux (Φ) through a closed surface is directly proportional to the charge (Q) enclosed within that surface. The mathematical representation of Gauss's Law is:
\[
\Phi = \frac{Q_{\text{in}}}{\epsilon_0}
...
Which of the following statement is correct ? If E = 0 , at all points of a closed surface. a. the electirc flux through the surface is zero. b. the total charge enclosed by the surface is zero.
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If the number of electric lines of force emerging out of a closed surfsace is 1000, then the charge enclosed by the surface is
If a uniform electric field in existing inside a cube, then the net charge enclosed inside the cube is ___
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If the total charge enclosed by a surface is zero, does it imply that the electric field everywhere on the surface is zero ? Conversely, if the electric field everywhere on a surface is zero, does it imply that net charge inside is zero.
A cylindrical suface is placed in uniform electric field in such a manner that axis of cylinder is parallel to the electric field intensity . Using the Gauss's law , prove that the net charge enclosed by this cylindrical surface must be zero.
5x10^(5) lines of electric flux are entering in a closed surface and 4x10^(5) liner come out of the surface the charge enclosed by the surface is-
A solid insulating sphere of radius a carries a net positive charge 3Q , uniformly distributed throughout its volume. Concentric with this sphere is a conducting spherical shell with inner radius b and outer radius c and having a net charge -Q, as shown in figure a. Consider a spherical Gaussian surface of radius rgtc, the net charge enclosed by this surface is ............. b. The direction of the electric field rgtc is ............. c. The electric field at rgtc is ............... . d. The electric field in the region with radius r, which cgtrgtb, is ............... e. Consider a spherical Gaussian surface of radius r, where cgtrgtb , the net charge enclosed by this surface is ................ . f. Consider a spherical Gaussian surface of radius r, where bgtrgta , the net charge enclosed by this surface is ................. . g. The electric field in the region bgtrgta is ................ . h. Consider a spherical Gaussian surface of radius rlta . Find an expression for the net charge Q(r) enclosed by this surface as a function of r. Note that the charge inside the surface is less than 3Q. i. The electric field in the region rlta is ................. . j. The charge on the inner surface of the conducting shell is .......... . k. The charge on the outer surface of the conducting shell is .............. . l. Make a plot of the magnitude of the electric field versus r.
