Home
Class 12
PHYSICS
Two batteries of emf epsilon1 and epsilo...

Two batteries of emf `epsilon_1 and epsilon_2 (epsilon_2 gt epsilon_1)` and internal resistances `r_1 and r_2` respectively are connected in parallel as shown in figure.

A

The equivalent emf `epsilon_(eq)` of the two cells is between `epsilon_1and epsilon_2`, i.e. `epsilon_1 lt epsilon_(eq) lt epsilon_2` .

B

The equivalent emf `epsilon_(eq)` is smaller than `epsilon_1`

C

The `epsilon_(eq)` is given by `epsilon_(eq)= epsilon_1+epsilon_2` always.

D

`epsilon_(eq)` is independent of internal resistances `r_1 and r_2`.

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER 9

    EDUCART PUBLICATION|Exercise SECTION - B|22 Videos
  • SAMPLE PAPER 9

    EDUCART PUBLICATION|Exercise SECTION - C|3 Videos
  • SAMPLE PAPER 7

    EDUCART PUBLICATION|Exercise SECTION-C|6 Videos
  • SAMPLE PAPER SELF- ASSESSMENT -(10)

    EDUCART PUBLICATION|Exercise SECTION-B|17 Videos

Similar Questions

Explore conceptually related problems

Two batteries of emf epsilon_(1) and epsilon_(2) (epsilon_(2)gtepsilon_(1) and internal resistances r_(1) and r_(2) respectively are connected in parallel as shown in Fig. 2 (EP).1.

Two batteries of emf epsi_(1) and epsi_(2)(epsi_(2) gt epsi_(1)) and internal resistance r_(1) and r_(2) respectively are connected in parallel as shown in figure.

Two batteries of emf E_(1) and E_(2)(E_(2) gt E_(1)) and internal resistance r_(1) and r_(2) respectively are connected in parallel as shown in the figure. Then, which of the followings statements is correct ?

Two batteris of emf epsilon_(1) and epsilon_(2) wit respective internal resistance r_(1) and r_(2) are connected in parallel. Now

Two cells of emfs epsilon_(1)and epsilon_(2) and internal resistances r_(1)and r_(2) respectively are connected in parallel . Obtain expressions for the equivalent (i) resistance and , (ii) emf of the combination.

Find the emf epsilon and the internal resistance r of an electric source which is equivalent to two batteries of emf's epsilon_(1) " and " epsilon_(2) and internal resistances r_(1) " and r_(2) , connected in parallel.

A battery of emf epsilon_0=10V is connected across a 1m long uniform wire having resistance 10Omega//m. Two cells of emf epsilon_1=2V and epsilon_2=4V having internal resistance 1Omega and 5Omega respectively are connected as shown in the figure. If a galvanometer shows no deflection at the point P , find the distance of point P from the point a .

A battery of emf E_(0) = 12 V is connected across a 4 m long uniform wire having resistance (4 Omega)/(m) . The cells of small emfs epsilon_(1) = 2 V and epsilon_(2) - 4 V having internal resistance 2 Omega and 6 Omega respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point N , the distance of point N from teh point A is equal to