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If a(ij)=|2i + 3j^(2)|, then matrix A(2x...

If `a_(ij)=|2i + 3j^(2)|,` then matrix `A_(2xx2) = [a_(ij)]` will be:

A

`[(5,-14),(7,16)]`

B

`[(5,14),(-7,16)]`

C

`[(5,14),(7,16)]`

D

`[(5,14),(7,-16)]`

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To construct the matrix \( A \) of order \( 2 \times 2 \) given the elements defined by \( a_{ij} = |2i + 3j^2| \), we need to calculate each element of the matrix based on the values of \( i \) and \( j \). ### Step-by-Step Solution: 1. **Identify the Matrix Elements**: The matrix \( A \) will have the following elements: \[ A = \begin{bmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{bmatrix} \] where \( a_{ij} = |2i + 3j^2| \). 2. **Calculate \( a_{11} \)**: For \( i = 1 \) and \( j = 1 \): \[ a_{11} = |2(1) + 3(1)^2| = |2 + 3| = |5| = 5 \] 3. **Calculate \( a_{12} \)**: For \( i = 1 \) and \( j = 2 \): \[ a_{12} = |2(1) + 3(2)^2| = |2 + 3 \times 4| = |2 + 12| = |14| = 14 \] 4. **Calculate \( a_{21} \)**: For \( i = 2 \) and \( j = 1 \): \[ a_{21} = |2(2) + 3(1)^2| = |4 + 3| = |7| = 7 \] 5. **Calculate \( a_{22} \)**: For \( i = 2 \) and \( j = 2 \): \[ a_{22} = |2(2) + 3(2)^2| = |4 + 3 \times 4| = |4 + 12| = |16| = 16 \] 6. **Construct the Matrix**: Now that we have all the elements, we can construct the matrix \( A \): \[ A = \begin{bmatrix} 5 & 14 \\ 7 & 16 \end{bmatrix} \] ### Final Answer: The matrix \( A \) is: \[ A = \begin{bmatrix} 5 & 14 \\ 7 & 16 \end{bmatrix} \]
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