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The magnetic flux linked with the coil ...

The magnetic flux linked with the coil (in Weber) is given by theequation
`phi = 5t^(2) + 3t + 16`
The induced EMF in the coil at time, t=4 will be-

A

`-27V`

B

`-43V`

C

`-108V`

D

`210V`

Text Solution

Verified by Experts

The correct Answer is:
B
Given `phi=5t^(2)+3t+16`
`epsi=-(dpi)/(dt)`
`=-(d)/(dt)[5t^(2)+3t+16]`
`epsi=-[10t+3]`
Hence at `t=4`
`epsi=-[10xx4+3]`
`=-43 V`
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