In a hydrogen atom the electron moves in an orbit of radius `0.5Å` making 10 revolutions per second, the magnetic moment associated with the orbital motion of the electron will be:

Options

A. `2.512xx10^(-38)xxAm^(2)`
B. `1.512xx10^(-38)xxAm^(2)`
C. `0.628xx10^(-38)xxAm^(2)`
D. Zero

Answer

B

Explanation

Given `r=0.5 Å=5xx10^(-11)m (n)/(t)=10` rev/s
Magnetic moment, m = NIA `=("neA")/(t)`
`I="ne"`
`A=pir^(2)`
`m=("ne" pi r^(2))/(t)`
`=10xx1.6xx10^(-19)xxpixx25xx10^(-22)`
`=16pixx25xx10^(-41)`
`=4pixx10^(-39)`
`=1.256xx10^(-38)Am^(2)`