How does Dibroane react with the following:
`NH_(3)`

Explanation

Diborane forms addition product with CO with symmetric cleavage.
`B_(2)H_(6)+2COto2BH_(3).CO`
b. With ammonia it forms an addition product with asymetric cleavage which on heating forms borazine which is known as inorganic benzene.
`3B_(2)H_(6)+6NH_(3)to3[BH_(2)(NH_(3))_(2)]^(+)[BH_(4)]^(-)`
`overset("heat")(to)2B_(3)N_(3)H_(6)+12H_(2)`