What is meant by the term Bond order? Calculate the bond orders in the following.
(a) `N_(2) " "` (b) `O_(2)" "` (c) `O_(2)^(+)" "` and (c) `O_(2)^(-)`

Explanation

Bond order is the number of bonds between two atoms. It is one half the difference bet ween the number of electrons present in te bonding and the antiboding orbitals.
Bond order `=1/2[N_(b)-N_(a)]`
Where `N_(b)` is the number of electrons in bonding molecular orbitals while `N_(a)` is the number of electons in antibonding moleculars orbitals. For calculating bond order electrons present in valence only ar considered.
a. MO electronic configuration of `N_(2)` molecule is
`(sigma_(g)1s)^(2)(sigma_(g)^(**)1s)^(2).(sigma_(g)2s^(2))(sigma_(g)^(**)2s^(2))`
`(pi2p^(2)=pi2p^(2))(sigma_(g)2p)^(2)`
Bond order `=(10-4)/2=6/2=3`