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Calculate the 'spin only' magnetic momen...

Calculate the 'spin only' magnetic moment of `Fe_(aq)^(2+)` ion.

Text Solution

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Fe (26) Electronic configuration `[Ar]3d^(6). 4s^(2)`
`Fe^(2+)` Electronic configuration is `[Ar]3d^(6)`
No. of unpaired electrons is `4`.
Spin only formula `mu =sqrt( n ( n+2) ) = sqrt( 4 xx 6) = sqrt(24) = 4.9" BM"`
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