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Find the equation of the ellipse whose f...

Find the equation of the ellipse whose focus is (0,3),eccentricity is `3/5` and the directrix is 3y - 25 = 0

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The equation of the ellipse whose focus is (3, -2), eccentricity 3/4 an directrix 2x-y+3=0

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Knowledge Check

  • IF the equation of the hyperbola whose focus is ( 2,4) eccentricity is 5 and directrix is 4x-3y + 1 =0 " is " 15x ^(2) -24xy + 8y^(2) +ax+ by + c= 0 then the ascending order of a,b,c is

    A
    a,b,c
    B
    b,c,a
    C
    c,a,b
    D
    c,b,a
  • The equation of the hyperbola whose focus is origin, eccentricity sqrt2 and directrix x+y+1=0 is

    A
    ` 15x^(2) -24xy + 8y^(2) +12x + 2y -19 =0 `
    B
    ` 2xy + 2x+2y +1=0`
    C
    `11x^(2) +24xy + 4y^(2) -74x - 48y + 99=0 `
    D
    ` 7x^(2) +12xy -2y^(2) -2x + 14y -22=0`
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    (i) Find the equation of the ellipse whose focus (-1,1)’e = 1/2 and directrix is x - y + 3 = 0 (ii) Find the equation of the ellipse with focus at (l,-l),e = 2 //3 and directrix as x + y + 2 = 0 .