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In a beaker 50 ml of a normal HCl soluti...

In a beaker 50 ml of a normal HCl solution was taken and `NH_3` gas was passed through it for some time. The contents of the beaker were then titrated, which required 60 ml of semi normal NaOH solution. How much ammonia was passed through the beaker.

A

0.85 g

B

0.34 g

C

0.51 g

D

0.4 g

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(1N)(HCl)+NH_3` [Neutralized by NaOH 60 ml (Semi normal `1//2` N)]
`{:(HCl + NH_3 ,rarr NH_4Cl),(N_1V_1,=N_2V_2),((HCl),"(NaOH)"):}`
`{:(N_1V_1 -, "mili eq. of "NH_3 ,= N_2V_2),(50xx1-," x",=1/2xx60),(,,=1/2xx60),(,,=30ml):}`
Meq. of HCI = 50 - 30 = 20 ml
Meq. of `NH_3 = (20)/1000 = 0.02`
Molar mass of `NH_3 = 14 +1xx3`
= 17
Wt. of `NH_3` = Meq. `xx` Molar mass of `NH_3`
`= 0.02 xx 17 `
= 0.34 gm
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