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RCH (2) OH + Cr O (3) overset ( aq. H (2...

`RCH _(2) OH + Cr O _(3) overset ( aq. H _(2) SO _(4))to Z + Cr^( X+)`
The oxidation number 'x' of Cr will be

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The correct Answer is:
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`{:(RC H_(2) OH + Cr O _(3)),(ubrace((1 ^(@)"Alcohol"))),(("Orange Solution")):}`
`overset( Aq. H _(2) SO _(4)) to underset(("Greenish opaque solution")) underset((Z))( RCOOH) + Cr ^(3+)`
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