Find the magnetic field at point P due to a straight -line segment AB of length 6 cm carrying a current of 5A. (see figure) `(mu_(0)=4pixx10^(-7)N-A^(-2))`

Options

A. `1.5 xx 10 ^(-5)T`
B. `2. 0 xx 10 ^(-5) T`
C. `2. 0 xx 10 ^(-5) T`
D. `2. 5 xx 10 ^(-5) T`

Answer

B

Explanation

`B = ( mu _(0) i )/( 4pir ) [ sin theta _(1) + sin theta_(2)]`
`= 10 ^(-7) xx (5)/(4 xx 10 ^(-2)) [ (3)/(5) + (3)/(5)]`
`B = 1 . 5 xx 10 ^(-5) T`