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In the Young's double slit experiment, t...

In the Young's double slit experiment, the spacing between two slits is `0.1mm`. If the screen is kept at a distance of `1.0m` from the slits and the wavelength of ligth is `5000Å`, then the fringe width is

A

`1.0cm`

B

`1.5 cm`

C

`0.5 cm `

D

`2.0cm`

Text Solution

Verified by Experts

The correct Answer is:
C
Fringe width is given by
`beta = ( lamda D )/( d )`
`beta = ( ( 5000 xx 10 ^(-10)))/( 0.1 xx 10 ^(-3)) = 5 xx 10 ^(-3) `
` beta = 0.5 cm`
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