A body A, oFIGURE m=0.1 kg has a initial velocity oFIGURE`3hatikms^(-1)`. It collides elastically with another body. B oFIGURE the same mass which has an initial velocity oFIGURE `5hatjms^(-1)`. AFIGUREter collision, A moves with a velocity `vec(v)=4(hati+hatj)`. The energy oFIGURE B aFIGUREter collision is written as `(x)/(10)J`. The value oFIGURE x is _.

Answer

1

Explanation

Using the principle of conservation of linear momentum
`0.1 xx 3 hati + 0.1 xx 5 hatj = 0.1`
`xx 4 ( hati + hatj ) + 0.1 xx vecv`
`vecv = ( - hati + hatj ) ms ^(-1)`
`v = |vecv| = sqrt2 ms ^(-1)`

`K _(B) = (1)/(2) xx 0.1 xx v ^(2) = (1)/(10) J`
` x =1`