In the figure D, E are points on the sides AB and AC respectively of `DeltaABC` such that `ar(DeltaDBC) = ar(DeltaEBC)` . Prove that DE || BC.

In the figure D,E are the midpoints of the sides AB and AC. IF DE=4cm, then BC=

In the figure, D, E are the midpoints of the sides AB and AC. If DE=4 cm,then BC=

In the figure, D,E are the midpoints of the sides AB and AC. If DE = 4 cm, then BC =

P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD show that ar(DeltaAPB) = ar Delta(BQC)

In the figure, D,E are mid-points of AB and AC then DeltaADE:squareBCED =

In the figure, ΔABC, D, E, F are the midpoints of sides BC, CA and AB respectively. Show that (i) BDEF is a parallelogram (ii) ar(DeltaDEF)=1/4ar(DeltaABC) (iii) ar(BDEF)=1/2ar(DeltaABC)

In the figure, D and E are the points on sides AB and AC of /_\ABC such that DE|\|BC. and divides △ABC into two parts, equal in area, Find AB BD ​ .

D,E,F are midpoints of sides BC,CA,AB of DeltaABC . Find the ratio of areas of DeltaDEF and DeltaABC .

In the figure, D and E are the points on sides AB and AC of triangle ABC such that DE || B C. " if "angle B = 30^(@) and angle A = 40^(@), find (i) x (ii) y (iii) z