Home
Class 12
PHYSICS
The motion of a particle along a straigh...

The motion of a particle along a straight line is described by the function `s = 6 + 4t^2 - t^4` in SI units. Find the velocity, acceleration, at t = 2s, and the average velocity during `3^(rd)` second.

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Find the velocity function The displacement of the particle is given by the function: \[ s(t) = 6 + 4t^2 - t^4 \] To find the velocity \( v(t) \), we differentiate the displacement function with respect to time \( t \): \[ v(t) = \frac{ds}{dt} = \frac{d}{dt}(6 + 4t^2 - t^4) \] ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    AAKASH SERIES|Exercise EXERCISE -I|58 Videos
  • MOTION IN A STRAIGHT LINE

    AAKASH SERIES|Exercise EXERCISE -II|80 Videos
  • MOTION IN A PLANE

    AAKASH SERIES|Exercise QUESTION FOR DESCRIPTIVE ANSWER|7 Videos
  • MOVING CHARGES AND MAGNETISM

    AAKASH SERIES|Exercise EXERCISE-III|49 Videos

Similar Questions

Explore conceptually related problems

The motion of a particle along a straight line is described by the function x=(2t -3)^2, where x is in metres and t is in seconds. Find (a) the position, velocity and acceleration at t=2 s. (b) the velocity of the particle at origin.

The motion of a particle along a straight line is described by the function x=(2t -3)^2, where x is in metres and t is in seconds. Find (a) the position, velocity and acceleration at t=2 s. (b) the velocity of the particle at origin.

The motion of a particle along a straight line is described by equation : x = 8 + 12 t - t^3 where x is in meter and t in second. The retardation of the particle when its velocity becomes zero is.

The motion of a particle along a straight line is described by equation : x = 8 + 12 t - t^3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is.

At time t , the displacement of a particle moving in a straight line by x = - 4t^(2) +2t . Find the velocity and acceleration a when t = (1/2) s .

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :

The position of an object moving on a straight line is defined by the relation x=t^(3)-2t^(2)-4t , where x is expressed in meter and t in second. Determine (a) the average velocity during the interval of 1 second to 4 second. (b) the velocity at t = 1 s and t = 4 s, (c) the average acceleration during the interval of 1 second to 4 second. (d) the acceleration at t = 4 s and t = 1 s.

A particle moves along a staight line such that its displacement at any time t is given by s=t^3-6t^2+3t+4m . Find the velocity when the acceleration is 0.

The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is