Home
Class 12
PHYSICS
A particle moves according to the equati...

A particle moves according to the equation `t= sqrtx +3`, where will be the particle come to the rest for the first time

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the given equation and find out when the particle comes to rest. The equation provided is: \[ t = \sqrt{x} + 3 \] ### Step-by-Step Solution: 1. **Understand the Equation**: The equation relates time \( t \) to position \( x \). We need to find the velocity of the particle, which is the rate of change of position with respect to time. ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    AAKASH SERIES|Exercise EXERCISE -I|58 Videos

  • MOTION IN A STRAIGHT LINE

    AAKASH SERIES|Exercise EXERCISE -II|80 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise QUESTION FOR DESCRIPTIVE ANSWER|7 Videos

  • MOVING CHARGES AND MAGNETISM

    AAKASH SERIES|Exercise EXERCISE-III|49 Videos

Similar Questions

Explore conceptually related problems

A particle moves according to the equation t = ax^(2)+bx , then the retardation of the particle when x = (b)/(a) is

A particle moves according to the equation x= a cos pi t . The distance covered by it in 2.5 s is

Consider a particle moving in simple harmonic motion according to the equation x=2.0cos(50pit+tan^-1 0.75) where x is in centimetre and t in second. The motion is started at t=0. a. When does the particle come to rest for the first time? B. When does the acceleration have its maximum magnitude for the first time? c. When does the particle comes to rest for the second time?

A particle moves in x-y plane according to the equations x= 4t^2+ 5t+ 16 and y=5t where x, y are in metre and t is in second. The acceleration of the particle is

The acceleration of a'particle starting from rest, varies with time according to the relation a=kt+c . The velocity of the particle after time t will be :

If a particle moves according to the law s=6t^(2)-(t^(3))/(2) , then the time at which it is momentarily at rest is

The position x of a particle moving along x - axis at time (t) is given by the equation t=sqrtx+2 , where x is in metres and t in seconds. Find the work done by the force in first four seconds

A particle moves according to the law x = rcos (pi)t/(2) The distance covered by it in the time interval between t=0 to t=3s is

A particle moves according to the law, x=acos(pit//2). . What is the distance covered by it in time interval t=0 to t=3 second.

A particle moves along a straight line on y-axis. The distance of the particle from O varies with time and is given by : y = 20t - t^2 . The distance travelled by the particle before it momentarily comes to rest is