A body is projected vertically up with velocity u from a tower. It reaches the ground with velocity nu. The height of the tower is `H=u^2/(2g)(n^2-1)`

Explanation

To solve the problem, we will use the equations of motion under uniform acceleration. The body is projected vertically upward with an initial velocity \( u \) and reaches the ground with a final velocity \( nu \). We need to find the height \( H \) of the tower.

### Step-by-step Solution:

1. **Identify the known variables**:
- Initial velocity, \( u \)
- Final velocity, \( v = nu \)
- Acceleration due to gravity, \( g \) (acting downwards)
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