A parachutist drops freely from an aeroplane for 10 seconds before the parachute opens out.Then he descends with a net retardation of `2m//sec^(2)`.
His velocity whe he reaches the ground is 8m/sec.Find the height at which he get out of the aeroplane?

Explanation

To find the height from which the parachutist jumps from the aeroplane, we will break down the problem into two parts: the free fall before the parachute opens and the descent after the parachute opens.

### Step 1: Calculate the velocity after 10 seconds of free fall
The parachutist falls freely under gravity for 10 seconds. The acceleration due to gravity (g) is approximately \(9.8 \, \text{m/s}^2\).

Using the first equation of motion:
\[
v = u + gt
...