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A person travelling on a straight line m...

A person travelling on a straight line moves with a uniform velocity `v_1` for a distance x and with a uniform velocity `v_2` for the next equal distance. The average velocity v is given by

A

`v=(v_1+v_2)/2`

B

`v=sqrt(v_1v_2)`

C

`2/v=1/v_1+1/v_2`

D

`1/v=1/v_1+1/v_2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will calculate the average velocity of a person traveling with two different uniform velocities over equal distances. ### Step 1: Understand the problem The person travels a distance \( x \) with a velocity \( v_1 \) and then travels another distance \( x \) with a velocity \( v_2 \). We need to find the average velocity \( v \) for the entire journey. ### Step 2: Calculate total displacement The total displacement \( D \) is the sum of the two distances traveled: \[ D = x + x = 2x \] ### Step 3: Calculate total time taken To find the total time \( T \), we will calculate the time taken for each segment of the journey. - Time taken to travel the first distance \( x \) with velocity \( v_1 \): \[ T_1 = \frac{x}{v_1} \] - Time taken to travel the second distance \( x \) with velocity \( v_2 \): \[ T_2 = \frac{x}{v_2} \] Now, we can find the total time \( T \): \[ T = T_1 + T_2 = \frac{x}{v_1} + \frac{x}{v_2} \] ### Step 4: Simplify the total time Factor out \( x \) from the total time equation: \[ T = x \left( \frac{1}{v_1} + \frac{1}{v_2} \right) \] ### Step 5: Calculate average velocity The average velocity \( v \) is given by the formula: \[ v = \frac{\text{Total Displacement}}{\text{Total Time}} = \frac{D}{T} \] Substituting the values we found: \[ v = \frac{2x}{x \left( \frac{1}{v_1} + \frac{1}{v_2} \right)} \] ### Step 6: Cancel \( x \) Since \( x \) appears in both the numerator and denominator, we can cancel it out: \[ v = \frac{2}{\frac{1}{v_1} + \frac{1}{v_2}} \] ### Step 7: Final expression for average velocity To express this in a more standard form, we can take the reciprocal: \[ \frac{1}{v} = \frac{1}{2} \left( \frac{1}{v_1} + \frac{1}{v_2} \right) \] Thus, we can express the average velocity as: \[ v = \frac{2v_1v_2}{v_1 + v_2} \] ### Final Answer The average velocity \( v \) is given by: \[ v = \frac{2v_1v_2}{v_1 + v_2} \] ---
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AAKASH SERIES-MOTION IN A STRAIGHT LINE -EXERCISE -I
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  4. Which of following statements is incorrect?

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  10. At time t = 0, two bodies A and B at the same point. A moves with cons...

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  11. Two bodies of different masses are dropped similtaneously from the top...

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  12. At a metro station, a girl walks up a stationary escalator in time t1....

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  13. Two bodies of different masses are dropped simultaneously from the top...

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  14. The acceleration of a moving body can be found from

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  15. A body falls freely from a height 'h' its average velocity when it rea...

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  16. For a moving body at any instant of time

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  17. A body falls freely from a height 'h' after two seconds if accelaratio...

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  18. A body falls freely from a height 'h' after two seconds if we assume t...

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