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Mark the correct statements for a partic...

Mark the correct statements for a particle go ing on a straight line:
(a) If the velocity and acceleration have opposite sign, the object is slowing down.
(b) If the position and velocity have opposite sign, the particle is moving towards the origin.
(c) If the velocity is zero at an instant, the acceleration should also be zero at that instant.
(d) If the velocity is zero for a time interval, the acceleration is zero at any instant within the time interval.

A

a, b & c are correct

B

b & d are correct

C

a, b & d are correct

D

all are correct

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AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze each statement one by one and determine whether they are correct or incorrect based on the principles of motion in a straight line. ### Step-by-Step Solution: 1. **Statement (a)**: "If the velocity and acceleration have opposite signs, the object is slowing down." - **Analysis**: When velocity and acceleration have opposite signs, it means that the object is decelerating. For example, if an object is moving in the positive direction (positive velocity) and the acceleration is negative, the object is slowing down. Therefore, this statement is **correct**. 2. **Statement (b)**: "If the position and velocity have opposite signs, the particle is moving towards the origin." - **Analysis**: If the position is positive and the velocity is negative, the particle is indeed moving back towards the origin. Conversely, if the position is negative and the velocity is positive, the particle is also moving towards the origin. Thus, this statement is **correct**. 3. **Statement (c)**: "If the velocity is zero at an instant, the acceleration should also be zero at that instant." - **Analysis**: This statement is not necessarily true. An object can have zero velocity while still experiencing acceleration (e.g., at the peak of a projectile's motion). Therefore, this statement is **incorrect**. 4. **Statement (d)**: "If the velocity is zero for a time interval, the acceleration is zero at any instant within the time interval." - **Analysis**: If the velocity is zero for a time interval, it does not imply that the acceleration is also zero. An object can have zero velocity but still have a non-zero acceleration during that time. For example, an object thrown upwards will have zero velocity at the peak but will have a downward acceleration due to gravity. Hence, this statement is **incorrect**. ### Summary of Correct Statements: - The correct statements are (a) and (b). ### Final Answer: - Correct statements: (a) and (b). ---
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AAKASH SERIES-MOTION IN A STRAIGHT LINE -EXERCISE -I
  1. Which of the following graph represents uniform motion

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  2. The area under acceleration-time graph gives

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  3. Which of the following velocity-time graphs shows a realistic situatio...

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  4. Consider the motion of the tip of the minute hand of a clock. In one h...

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  5. Which of the following velocity-time graphs represent uniform motion

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  6. A particle moves along x-axis and its x-coordinate changes with time a...

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  7. An object may have ( a) varying speed without having varying velocity...

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  8. Mark the correct statements for a particle go ing on a straight line: ...

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  9. The velocity of a particle is zero at t = 0. (a) The acceleration a...

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  10. The velocity time plot for a particle moving on straight line is show...

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  11. Velocity (v) versus displacement (x) plot of a body moving along a str...

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  12. Following are four different relation about displacement,velocity and...

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  13. For an object moving with uniform acceleration, travelling 50m in 5th ...

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  14. A body projected vertically with a velocity 'u' from the ground. Its v...

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  15. Read the following statements and choose the correct answer. (a) For...

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  16. Height of the body from the ground can be calculated by using the form...

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  17. A balloon from rest accelerates uniformly upward with 'a' ms^(-2), for...

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  18. In one dimensional motion, instantaneous speed v satisfies (0 le v lt ...

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  19. A particle starts from point A moves along a straight line path with a...

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  20. Assertion: Always |(dvecv)/(dt)|=d/(dt)|vecv| , where vecv has its usu...

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