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Assertion: Always |(dvecv)/(dt)|=d/(dt)|...

Assertion: Always `|(dvecv)/(dt)|=d/(dt)|vecv|` , where `vecv` has its usual meaning.
(Reason): Acceleration is rate of change of velocity.

A

Both (Assertion) and (Reason) are true and (Reason) is the correct explanation of (Assertion)

B

Both (Assertion) and (Reason) are true and (Reason) is not the correct explanation of (Assertion)

C

(Assertion) is true but (Reason) is false

D

(Assertion) is false but (Reason) is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and the reason provided: **Assertion:** \( \left| \frac{d\vec{v}}{dt} \right| = \frac{d}{dt} |\vec{v}| \) **Reason:** Acceleration is the rate of change of velocity. ### Step-by-Step Solution: 1. **Understand the Terms:** - Let \( \vec{v} \) be the velocity vector. - The magnitude of the velocity vector is denoted as \( |\vec{v}| \). 2. **Acceleration Definition:** - Acceleration \( \vec{a} \) is defined as the rate of change of velocity: \[ \vec{a} = \frac{d\vec{v}}{dt} \] 3. **Magnitude of Velocity:** - The magnitude of the velocity vector \( |\vec{v}| \) is given by: \[ |\vec{v}| = \sqrt{v_x^2 + v_y^2 + v_z^2} \] - If \( \vec{v} \) is expressed in terms of its components, we can differentiate \( |\vec{v}| \) with respect to time. 4. **Differentiating the Magnitude:** - Using the chain rule, we differentiate the magnitude of the velocity: \[ \frac{d}{dt} |\vec{v}| = \frac{d}{dt} \left( \sqrt{v_x^2 + v_y^2 + v_z^2} \right) \] - Applying the chain rule: \[ \frac{d}{dt} |\vec{v}| = \frac{1}{2\sqrt{v_x^2 + v_y^2 + v_z^2}} \cdot \left( 2v_x \frac{dv_x}{dt} + 2v_y \frac{dv_y}{dt} + 2v_z \frac{dv_z}{dt} \right) \] - This simplifies to: \[ \frac{d}{dt} |\vec{v}| = \frac{1}{|\vec{v}|} \left( v_x \frac{dv_x}{dt} + v_y \frac{dv_y}{dt} + v_z \frac{dv_z}{dt} \right) \] 5. **Comparing Both Sides:** - The left-hand side \( \left| \frac{d\vec{v}}{dt} \right| \) represents the magnitude of the acceleration vector. - The right-hand side \( \frac{d}{dt} |\vec{v}| \) does not always equal \( \left| \frac{d\vec{v}}{dt} \right| \) unless the direction of the velocity vector remains constant. 6. **Conclusion:** - The assertion \( \left| \frac{d\vec{v}}{dt} \right| = \frac{d}{dt} |\vec{v}| \) is not always true. It holds true only under specific conditions (e.g., when the direction of the velocity does not change). - Therefore, the assertion is **false** while the reason is **true**. ### Final Answer: - Assertion: False - Reason: True
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AAKASH SERIES-MOTION IN A STRAIGHT LINE -EXERCISE -I
  1. Which of the following graph represents uniform motion

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  2. The area under acceleration-time graph gives

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  3. Which of the following velocity-time graphs shows a realistic situatio...

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  4. Consider the motion of the tip of the minute hand of a clock. In one h...

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  5. Which of the following velocity-time graphs represent uniform motion

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  6. A particle moves along x-axis and its x-coordinate changes with time a...

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  7. An object may have ( a) varying speed without having varying velocity...

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  8. Mark the correct statements for a particle go ing on a straight line: ...

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  9. The velocity of a particle is zero at t = 0. (a) The acceleration a...

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  10. The velocity time plot for a particle moving on straight line is show...

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  11. Velocity (v) versus displacement (x) plot of a body moving along a str...

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  12. Following are four different relation about displacement,velocity and...

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  13. For an object moving with uniform acceleration, travelling 50m in 5th ...

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  14. A body projected vertically with a velocity 'u' from the ground. Its v...

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  15. Read the following statements and choose the correct answer. (a) For...

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  16. Height of the body from the ground can be calculated by using the form...

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  17. A balloon from rest accelerates uniformly upward with 'a' ms^(-2), for...

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  18. In one dimensional motion, instantaneous speed v satisfies (0 le v lt ...

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  19. A particle starts from point A moves along a straight line path with a...

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  20. Assertion: Always |(dvecv)/(dt)|=d/(dt)|vecv| , where vecv has its usu...

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