A bullet is fired from a gun . The force on the bullet is given by
` F = 600 - ( 2 xx 10^(5))` t
Here , F is in newton and t in second . The force on the bullet becomes zero as soon as it leaves the barrel . The impulse imparted to the bullet is

Explanation

`F=600-2xx10^(5)t`
F becomes zero as soon as the bullet leaves the barrel. `0=600-2xx10^(5)t , 600 = 2xx10^(5)t`
`t=3xx10^(-3)s` Impulse `= int_(0)^(1) Fdt`
`= int_(0)^(t)(600-2xx10^(5)t)dt=[600t-cancel(2)xx10^(5)(t^(2))/(cancel(2))]^(3xx10^(-3)`
`=600xx3xx10^(-3)-10^(5)xx9xx10^(-6)=0.9 Ns`