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Two ice skaters A and B approach each ot...

Two ice skaters A and B approach each other at right angles. A has mass 30 kg and velocity 1 mis and B has a mass of 20 kg and velocity 2 m/s. They meet and stick together. The final velocity of couple is :

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Let v = Composite velocity after collision, `theta` = angle with the direction of 30 kg mass Then from momentum conservation,
`50v cos theta=30xx1`
`50v sin theta =20xx2`
From equations (1) and (2),
`sqrt((50)^(2)+v^(2))=sqrt(900+1600)`
`50v=50`
`v=1m//s`
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