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A bomb of 1 kg is thrown vertically up w...

A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 seconds, it explodes into two parts. One of mass 400 gm goes down with speed 25 m/s. What will happen to the other part just after explosion

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After 5 sec, velocity of bomb
`v=u-"gt"=100-10xx5=50 m//s`
`therefore` initial momentum before explosion
`=1xx50 kg ms^(-1)`
From momentum consevation,
`1xx50=-0.4xx25+0.6 v`
`therefore v=100 m//s`, upwards.
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