A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of `4.9ms^(2)` (ii) lowered with an acceleration of `4.9ms^(-2)`. The ratio of tension in the first and second case is

Explanation

When mass is lifted up with acceleration
`4.9 m//s^(2), T_(1)=m(9.8+4.9)`
When mass is lowered with same acceleration,
`T_(2)=m(9.8-4.9)`
`therefore (T_(1))/(T_(2))=(14.7)/(4.9)=3:1`