The apparent weight of a person inside a lift is `w_(1)` when lift moves up with a certain accelration and is `w_(2)` when lift moves down with same acceleration. The weight of the person when lift moves up with constant speed is `:`

Explanation

(a) `w_(1)=w(1+(a)/(g)), w_(2)=w(1-(a)/(g))`
`w_(1)+w_(2)=2w rArr w=(w_(1)+w_(2))/(2)`
(b) `(w_(1))/(w_(2))=(cancel(w)(1+(a)/(g)))/(cancel(1-(a)/(g))) " " (g+a)/(g-a)=(w_(1))/(w_(2))`
`(g)/(a)=(w_(1)+w_(2))/(w_(1)-w_(2)) " " a=g((w_(1)-w_(2))/(w_(1)+w_(2)))`