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A 75 kg man stands in a lift . What forc...

A 75 kg man stands in a lift . What force does the floor exert on him when the elevator starts moving upwards with an acceleration of ` 2 ms^(-2)` Given : `g=10ms^(-2)` .

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Verified by Experts

R - mg = ma,
`R=mg+ma=m(g+a)`
`=75(10+2)N=900N`
`=(900)/(10)kg wt. = 90 kg. wt`
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