Two blocks are arranged as shown in figure. Find the ratio of `a_(1)//a_(2)`. (`a_(1)` is acceleration of `m_(1)` and `a_(2)` that of `m_(2))`

Explanation

`l_(1)+2l_(2)=` constant
differentiating the equation with respect to time
`a_(1)+2a_(2)=0 , T = m_(1)a_(1)`

`m_(2)g-2T=m_(2)a_(2), m_(2)a_(2) , m_(2)g = 2m_(1)a_(1)+m_(2)a_(2)`
`m_(2)g=2m_(1)(2a_(2))+m_(2)a_(2)`
`a_(2)=(m_(2)g)/(4m_(1)+m_(2)), a_(1)=(2m_(2)g)/(4m_(1)+m_(2))`