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A man of mass 40 kg is at rest between t...

A man of mass 40 kg is at rest between the walls as shown in the figure. If between the man and the walls is 0.8, find the normal reaction exerted by the walls on the man. (g = `10 ms^(-2)`)

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Since man is at rest,
`N_(1)-N_(2)=0`
`therefore N_(1)=N_(2)=N` (say)
`therefore 2mu N =mg`
`= 2xx0.8xxN=400`
`therefore N=250 N`
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