A rough inclined plane is inclined at 30° to the horizontal as shown in the figure. A uniform chain of length L is partly on the inclined plane and partly hanging from the top of the incline. If the coefficient offriction between chain and inclined plane is `mu`, the maximum length of the lianging part to prevent the chain from falling vertically is:

Explanation

`sigma xg = sigma (L-x)g sin 30+mu sigma(L-x)g cos 30`
`x=(L-x)(1)/(2)+mu(L-x)(sqrt(3))/(2)`
`therefore x=((1+sqrt(3)mu)L)/(sqrt(3)(mu+sqrt(3)))`