A stone of mass 2.0 kg is tied to the end of a string of 2m length. It is whirled in a horizontal circle. If the breaking tension of the string is 400 N, calculate the maximum velocity of the stone.

Explanation

`m=2.0 kg, r =2m`, tension = 400 N.
When the tension in the string reaches the breaking tension, the velocity of the body becomes maximum. Let the maximum velocity be v.
Tension = centripetal force
`400=(mv^(2))/(r ) rArr 400=(2xx v^(2))/(2)`
`v^(2)=400 , v=20 ms^(-1)`.