An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at `15^(@)`. What is the radius of the loop?

Explanation

If N is the normal force on the wings,
`N cos theta = mg " " N sin theta = (mv^(2))/(R )`
On simplification, `Tan theta = (v^(2))/(Rg)`
`R=(v^(2))/(g tan tan)=(200xx200)/(10xx tan 15^(@))=15 km`.