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A block of mass m is placed behind in co...

A block of mass m is placed behind in contact with vertical side of M as shown in the figure. The coefficient of static friction between m and M in `mu`. The least horizontal force with which m can be pushed so that the two blocks move together is (neglect friction between M and ground).

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To solve the problem, we need to determine the least horizontal force \( F \) that can be applied to the block of mass \( m \) so that both blocks \( m \) and \( M \) move together without the smaller block sliding down. ### Step-by-Step Solution: 1. **Identify the Forces Acting on Block \( m \)**: - The weight of block \( m \) acts downward: \( W_m = mg \). - The normal force \( N \) exerted by block \( M \) on block \( m \) acts upward. - The force of static friction \( f_s \) between the two blocks acts horizontally to the right, opposing the tendency of block \( m \) to slide down. ...
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