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A block is pushed up a rough inclined pl...

A block is pushed up a rough inclined plane of 45°. If the time of descent is twice the time of ascent, the coefficient of friction is

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`V=sqrt(2g(sin theta-mu cos theta)AC)`
`therefore CD = (V^(2))/(2mu g)`
`CD=(cancel(2)cancel(g)(sin theta - mu cos theta)AC)/(cancel(2) mu cancel(g))`
`mu CD=((AB)/(AC)-(mu BC)/(AC))AC`
`mu CD = AB-mu BC therefore mu = (AB)/(BD)`
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