A lift is ascending with a constnat speed V. A passenger in the lift drops a coin. The acceleration of the coin towards the floor will be

Options

A. zero
B. g
C. less than g
D. greater than g

Answer

To solve the problem, we need to analyze the situation step by step.

### Step 1: Understand the motion of the lift
The lift is ascending with a constant speed \( V \). This means that the lift is not accelerating; it is moving at a constant velocity.

**Hint:** Remember that constant speed implies zero acceleration.

### Step 2: Analyze the passenger's action
A passenger in the lift drops a coin. Since the lift is moving with a constant speed, the passenger and the coin are both initially moving upward with the same speed \( V \).

**Hint:** Consider the initial conditions of the coin when it is released.

### Step 3: Determine the forces acting on the coin
Once the coin is released, the only force acting on it is the force of gravity, which acts downward. The acceleration due to gravity is denoted as \( g \).

**Hint:** Identify the forces acting on the coin after it is dropped.

### Step 4: Apply Newton's second law of motion
According to Newton's second law, the net force acting on an object is equal to the mass of the object multiplied by its acceleration (\( F = ma \)). For the coin, the only force acting on it is its weight, which is \( mg \) (where \( m \) is the mass of the coin and \( g \) is the acceleration due to gravity).

**Hint:** Relate the forces acting on the coin to its acceleration.

### Step 5: Set up the equation
Since the only force acting on the coin is its weight, we can write:
\[ ma = mg \]
Here, \( a \) is the acceleration of the coin.

### Step 6: Solve for the acceleration of the coin
Dividing both sides of the equation by \( m \) (assuming \( m \neq 0 \)):
\[ a = g \]
This means that the acceleration of the coin towards the floor is equal to the acceleration due to gravity.

**Hint:** Simplify the equation to find the acceleration.

### Conclusion
The acceleration of the coin towards the floor will be \( g \), which is the acceleration due to gravity.

### Final Answer
The acceleration of the coin towards the floor will be \( g \).