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Mendel's principle of seggregation was b...

Mendel's principle of seggregation was based on the separation fo alleles in the garden pea during:

A

Embryonic development

B

Seed formation

C

Gamete formation

D

Pollination

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**Step-by-Step Solution:** 1. **Understanding Mendel's Principle of Segregation**: Mendel's principle of segregation states that during the formation of gametes, the two alleles for a trait separate from each other so that each gamete carries only one allele for each gene. 2. **Identifying the Context**: The question asks when the separation of alleles occurs in the garden pea. To answer this, we need to consider the processes involved in reproduction. 3. **Evaluating the Options**: - **Option 1: Embryonic Development**: This stage occurs after fertilization and does not involve the separation of alleles. - **Option 2: Seed Formation**: This occurs after fertilization and does not involve the segregation of alleles. - **Option 3: Gamete Formation**: This is the process where alleles segregate, as each gamete receives only one allele from each gene. - **Option 4: Pollination**: This is the transfer of pollen but does not involve the segregation of alleles. 4. **Conclusion**: The correct answer is **Option 3: Gamete Formation**, as this is the stage during which the alleles segregate.
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Mendel's law of segregation was based on the separation of alleles in the garden pea during:

A : Mendel gave postulates like "principles of segregation and principles of independent assortment" after studying seven pairs of contrasting traits in garden pea. R : He was lucky in selecting seven characters in pea that were located on seven different chromosomes.

Strong acid versus strong base: The principle of conductometric titrations is based on the fact that during the titration, one of the ions is replaced by the other and invariable these two ions differ in the ionic conductivity with the result that thhe conductivity of the solution varies during the course of the titration. take, for example, the titration between a strong acid, say HCl, and a string base, say NaOH before NaOH is added, the conductance of HCl solution has a high value due to the presence of highly mobile hydrogen ions. As NaOH is added, H^(+) ions are replaced by relatively slower moving Na^(+) ions. consequently the conductance of the solution decreases and this continues right upto the equivalence point where the solution contains only NaCl. Beyond the equivalence point, if more of NaOH is added, then the solution contains a excess of the fast moving OH^(-) ions with the result that its conductance is increased ad it condinues to increase as more and more of NaOH is added. If we plot the conductance value versus the amount of NaOH added, we get a curve of the type shown in Fig. The descending portion AB represents the conductances before the equivalence point (solution contains a mixture of acid HCl and the salt NaCl) and the ascending portion CD represents the conductances after the equivalence point (solution contains the salt NaCl and the excess of NaOH). The point E which represent the minium conductance is due to the solution containing only NaCl with no free acid or alkali and thus represents the equivalence point. this point can, however, be obtained by the extrapolation of the lines AB and DC, and therefore, one is not very particular in locating this point expermentally as it is in the case of ordinary acid-base titrations involving the acid-base indicators. Weak acid versus strong base: Let us take specific example of acetic acid being titrated against NaOH . Before the addition of alkali, the solution shows poor conductance due to feeble ionization of acetic acid. Initially the addition of alkali causes not only the replacement of H^(+) by Na^(+) but also suppresses the dissociation of acetic acid due to the common ion Ac^(-) and thus the conductance of the solution decreases in the beginning. but very soon the conductance start increasing as addition of NaOH neutralizes the undissociated HAc to Na^(+)Ac^(-) thus causing the replacement of non-conducting HAc with Strong-conducting electrolyte Na^(+)Ac^(-) . the increase in conductance continuous right up to the equivalence point. Beyond this point conductance increases more rapidly with the addition of NaOH due to the highly conducting OH^(-) ions, the graph near the equivalence point is curved due to the hydrolysis of the salt NaAc . The actual equivalence point can, as usual, be obtained by the extrapolation method. In all these graphs it has been assumed that the volume change due addition of solution from burrette is negnigible, hence volume change of the solution in beaker the conductance of which is measured is almost constant throughout the measurement. Q. The nature of curve obtained for the titration between weak acid versus strong base as described in the above passage will be:

In Mendel's breeding experiment on garden pea, the F_2 generation yielded the offspring in a ratio of 25% which produced pure yellow pods, 50% which produced hybrid seed pods and 25% pure green pods. (a) Which of the two colours of pods is dominant? (b) What are the phenotypes of the parents of the F_1 generation?

Mendel conducted hybridization experiments on Garden Pea of

AAKASH SERIES-PRINCIPLES OF INHERITANCE AND VARIATION-EXERCISE-I
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  2. The characters that are expressed in the first generation are called

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  3. Mendel's principle of seggregation was based on the separation fo alle...

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  4. Progeny are phenotypically and genotypically similar in

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  5. In the monohybrid cross the F(1) hybrid produces two kinds gametes eac...

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  6. How many types of combinations of gametes are possible in a monohybrid...

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  7. Mendel's law of segeration is based upon the F(2) ratio of

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  8. The postulate of Mendel that cannot be explained with monohybrid cross

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  9. The genotype of a dominant phenotype

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  10. Match following columns and identify the correct match.

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  11. A gamete normally contains

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  12. Coloured seed coat (S) is dominant over white seed coat (s). When a wh...

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  13. When a grey color seed producing pea plant is crossed to white color s...

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  14. A cross between F(1) plant with a plant which is phenotypically and ge...

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  15. Total types of gametes produced in monohybrid back cross plants

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  16. The genotypic ratio an phenotyti ratio of back cross and test cross of...

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  17. Identify the cross in which the genotypic ratio of F(2) is 1:2:1

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  18. The phenotypic ratio of incomplete dominance in F(2) is

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  19. The phenotypic ratio of co dominance in F(2) is

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  20. MN blood type is an example for

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