When true breeding pea plant with yellow cotyledons are round seeds is crossed to a plant with green cotyledons and wrinkled seeds the genotype of progeny will be

Options

A. YYRR
B. Yyrr
C. YyRr
D. yyRr

Answer

To determine the genotype of the progeny when a true breeding pea plant with yellow cotyledons and round seeds is crossed with a plant that has green cotyledons and wrinkled seeds, we can follow these steps:

### Step 1: Identify the Traits and Their Dominance
- Yellow cotyledons (Y) and round seeds (R) are dominant traits.
- Green cotyledons (y) and wrinkled seeds (r) are recessive traits.

### Step 2: Determine the Genotypes of the Parent Plants
- The true breeding plant with yellow cotyledons and round seeds must be homozygous for both traits. Therefore, its genotype is:
- Yellow cotyledons: YY (homozygous dominant)
- Round seeds: RR (homozygous dominant)
- The plant with green cotyledons and wrinkled seeds is also true breeding, so its genotype is:
- Green cotyledons: yy (homozygous recessive)
- Wrinkled seeds: rr (homozygous recessive)

### Step 3: Write the Genotypes of the Parent Plants
- Parent 1 (Yellow Round): YYRR
- Parent 2 (Green Wrinkled): yyrr

### Step 4: Perform the Cross
- When we cross these two plants, we can set up the cross as follows:
- YYRR (Yellow Round) x yyrr (Green Wrinkled)

### Step 5: Determine the Genotype of the Progeny
- The offspring (F1 generation) will inherit one allele from each parent for each trait:
- From the first parent (YYRR), the offspring will receive:
- Y from YY (Yellow)
- R from RR (Round)
- From the second parent (yyrr), the offspring will receive:
- y from yy (Green)
- r from rr (Wrinkled)

- Therefore, the genotype of the progeny will be:
- YyRr

### Step 6: Conclusion
- The genotype of the progeny when a true breeding pea plant with yellow cotyledons and round seeds is crossed with a plant with green cotyledons and wrinkled seeds is YyRr.

### Final Answer
The genotype of the progeny will be **YyRr**.

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