In a typical dihybrid cross the number of recombinants formed in the `F_(2)` generation is

Options

A. `2//16`
B. `10//16`
C. `9//16`
D. `6//16`

Answer

To solve the question regarding the number of recombinants formed in the F2 generation of a typical dihybrid cross, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Dihybrid Cross**: A dihybrid cross involves two traits, each represented by two alleles. For example, consider traits for seed shape (Round 'R' vs. Wrinkled 'r') and seed color (Yellow 'Y' vs. Green 'y').

2. **F1 Generation**: When two homozygous parents (RRYY and rryy) are crossed, the F1 generation will all be heterozygous (RrYy) and exhibit the dominant traits (Round Yellow seeds).

3. **F2 Generation**: The F1 generation (RrYy) is then self-crossed (RrYy x RrYy). The resulting F2 generation will show a phenotypic ratio of 9:3:3:1. This means:
- 9 individuals show both dominant traits (Round Yellow)
- 3 individuals show the dominant trait for the first character and the recessive trait for the second (Round Green)
- 3 individuals show the recessive trait for the first character and the dominant trait for the second (Wrinkled Yellow)
- 1 individual shows both recessive traits (Wrinkled Green)

4. **Identify Recombinants**: The recombinant phenotypes are those that differ from the parental combinations. In this case, the recombinants are:
- Round Green (3 individuals)
- Wrinkled Yellow (3 individuals)

5. **Total Recombinants**: Adding the number of individuals with recombinant phenotypes gives us:
- Round Green: 3
- Wrinkled Yellow: 3
- Total Recombinants = 3 + 3 = 6

6. **Calculate the Ratio**: The total number of offspring in the F2 generation is 16 (9 + 3 + 3 + 1). Therefore, the ratio of recombinants to the total number of offspring is:
- Recombinants = 6
- Total Offspring = 16
- Ratio = 6/16

### Final Answer:
The number of recombinants formed in the F2 generation of a typical dihybrid cross is **6/16**.

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