When true breeding yellow wrinkled seeded pea plant is crossed to true breeding green round seeded pea plant the progeny will be

Options

A. All yelow round
B. All yellow wrinkled
C. All green round
D. All green wrinkled

Answer

To solve the problem of what the progeny will be when a true breeding yellow wrinkled seeded pea plant is crossed with a true breeding green round seeded pea plant, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Traits**:
- Yellow seeds (Y) and round seeds (R) are dominant traits.
- Wrinkled seeds (y) and green seeds (r) are recessive traits.

2. **Determine the Genotypes of the Parents**:
- The true breeding yellow wrinkled seeded plant will have the genotype: **YYrr** (homozygous dominant for yellow and homozygous recessive for wrinkled).
- The true breeding green round seeded plant will have the genotype: **yyRR** (homozygous recessive for green and homozygous dominant for round).

3. **Set Up the Cross**:
- We will cross YYrr (yellow wrinkled) with yyRR (green round).

4. **Use a Punnett Square**:
- To visualize the cross, we can set up a Punnett square.
- The gametes from the yellow wrinkled plant (YYrr) will be: **Yr** (all gametes will carry Y and r).
- The gametes from the green round plant (yyRR) will be: **yR** (all gametes will carry y and R).

5. **Fill in the Punnett Square**:
- The combinations from the gametes will be:
- YyRr (Yellow Round)
- YyRr (Yellow Round)
- YyRr (Yellow Round)
- YyRr (Yellow Round)

6. **Analyze the Progeny**:
- All progeny will have the genotype **YyRr**, which means they will express the dominant traits.
- Therefore, all progeny will be **Yellow Round**.

### Conclusion:
The progeny of the cross between a true breeding yellow wrinkled seeded pea plant and a true breeding green round seeded pea plant will be **all yellow round**.