Home
Class 12
BIOLOGY
A test cross of F(1) flies +a/+b produce...

A test cross of `F_(1)` flies +a/+b produced the followings,
++/ab(R) 9`" "` ab/ab(R)9
+b/ab(R) 41`" "`a+/ab(R)41
This cross represents

A

Trans configuration

B

Cis configuration

C

Complete linkage

D

No crossing over

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given test cross results and determine the type of genetic configuration represented by the F1 flies with the genotype +a/+b. ### Step-by-Step Solution: 1. **Understanding the Test Cross**: - A test cross involves crossing an individual with a homozygous recessive individual to determine the genotype of the former. In this case, the F1 flies have the genotype +a/+b. 2. **Interpreting the Results**: - The offspring from the test cross are: - ++/ab (R) - 9 - ab/ab (R) - 90 - +b/ab (R) - 41 - a+/ab (R) - 41 - The numbers next to each genotype indicate the frequency of each type of offspring. 3. **Identifying Recombinants and Parental Types**: - The parental types are those that match the original F1 genotype (+a/+b) and the homozygous recessive (ab/ab). - The recombinant types are those that differ from the parental types, which in this case are ++/ab, +b/ab, and a+/ab. 4. **Calculating Recombinant Frequencies**: - The total number of offspring is: 9 (++) + 90 (ab) + 41 (+b) + 41 (a+) = 181. - The recombinant types are ++/ab (9) + +b/ab (41) + a+/ab (41) = 91. - The recombinant frequency = (Number of recombinants / Total offspring) = 91 / 181. 5. **Determining Linkage**: - A high number of parental types (90) compared to the number of recombinants (91) suggests that the genes are linked. - If there were no linkage, we would expect a more even distribution of offspring types. 6. **Identifying the Configuration**: - The F1 genotype +a/+b indicates that the two dominant alleles are on different homologous chromosomes (trans configuration). - In trans configuration, the dominant alleles are not on the same chromosome, which is consistent with the observed offspring ratios. 7. **Conclusion**: - Based on the analysis, the test cross represents a trans configuration. ### Final Answer: The cross represents **trans configuration**. ---
Promotional Banner

Topper's Solved these Questions

  • PRINCIPLES OF INHERITANCE AND VARIATION

    AAKASH SERIES|Exercise EXERCISE -II (Sex determination & Genetic Disorders)|46 Videos
  • PRINCIPLES OF INHERITANCE AND VARIATION

    AAKASH SERIES|Exercise EXERCISE -II (NCERT Examplar problems)|18 Videos
  • PRINCIPLES OF INHERITANCE AND VARIATION

    AAKASH SERIES|Exercise EXERCISE-I (Sex determination & Genetic Disorders)|44 Videos
  • PRINCIPLES AND PROCESSES

    AAKASH SERIES|Exercise Exercise - III (Previous AIPMT/NEET Questions)|26 Videos
  • RESPIRATION IN PLANTS

    AAKASH SERIES|Exercise Exercise - III|9 Videos

Similar Questions

Explore conceptually related problems

Add the following : 5a, 9a and 14ab

If a^(2) + b^(2) = 41 and ab = 4 , find : (i) a-b

If a^(2) + b^(2) = 41 and ab = 4 , find : (ii) a+b

If a + b= 9 and ab = -22 , find : a^(2)- b^(2)

A heterozygous individual ++ab is crossed to its revessive parent and has produced the offsprings in the following proportion. ++//ab-200 a+//ab-50 +b//ab-30 ab//ab-100 What is the expected distance between the two gene loci ?

If a + b= 9 and ab = -22 , find : a-b

Factorise : a^(2)b^(2) + 8ab - 9

A and B genes are linked .what shall be genotype of progeny in a cross between AB/ab and ab/ab?

The range of ab if |a|le1" and "a+b=1,(a, b in R), is

Find R_(AB) in the circuit shown in figure.

AAKASH SERIES-PRINCIPLES OF INHERITANCE AND VARIATION-EXERCISE -II
  1. Lack of independent assortment of two genes A and B in fruit fly Droso...

    Text Solution

    |

  2. An individual homozgous for genes cd is crossed with wild type and F(1...

    Text Solution

    |

  3. A test cross of F(1) flies +a/+b produced the followings, ++/ab(R) 9...

    Text Solution

    |

  4. Assume that genes a and b are linked and show 40 % reombination. If ++...

    Text Solution

    |

  5. In a linear chromosome map, distances between 4 loci is as follows, a-...

    Text Solution

    |

  6. What will be the phenotypic ratio in a situation of complementary gene...

    Text Solution

    |

  7. If gene freuency between genes a and c 2%, b and c 13%, b and d 4%, a ...

    Text Solution

    |

  8. The crossing over between homologous chromosomes never exceeds beyond

    Text Solution

    |

  9. Cis tans expression of genes is an example of

    Text Solution

    |

  10. In a genetic cross having recessive epistasis, F(2) phenotypic ratio w...

    Text Solution

    |

  11. Independent genes that copy other genes so as to produce a similar eff...

    Text Solution

    |

  12. Chromosome map is useful for

    Text Solution

    |

  13. The percentage of recombination involving the seed shape and seed colo...

    Text Solution

    |

  14. Genetic map is one that

    Text Solution

    |

  15. Distance between the genes and percentage of recombination shows.

    Text Solution

    |

  16. Type of gene mutation which involves replacement of purine with pyrimi...

    Text Solution

    |

  17. Mutations induced by 5-bromo uracil are

    Text Solution

    |

  18. Given below is the representation of a kind of chromosomal mutation: ...

    Text Solution

    |

  19. Inversion without involving the centromere is called

    Text Solution

    |

  20. Aneuploidy which results in loss of a complete homologous pair of ch...

    Text Solution

    |