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The two plates X and Y of a parallel pla...

The two plates X and Y of a parallel plate capacitor of capacitance C are given a charge of amount Q each. X is now joined to the positive terminal and Y to the negative terminal of a cell of emf E = Q/C: -

A

Charge of amount Q will flow from the negative terminal to the positive terminal of the cell inside

B

The total charge on the plate X will be 2Q.

C

The total charge on the plate Y will be zero.

D

The cell will supply `CE^2` amount of energy.

Text Solution

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The correct Answer is:
A, B, C, D
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